Graph-structured stack: Difference between revisions
Appearance
Content deleted Content added
m change source to syntaxhighlight |
|||
Line 11: | Line 11: | ||
==Operations== |
==Operations== |
||
< |
<syntaxhighlight lang="cpp"> |
||
GSSnode* GSS::add(GSSnode* prev, int elem) |
GSSnode* GSS::add(GSSnode* prev, int elem) |
||
{ |
{ |
||
Line 32: | Line 32: | ||
return node; |
return node; |
||
} |
} |
||
</syntaxhighlight> |
|||
</source> |
|||
< |
<syntaxhighlight lang="cpp"> |
||
void GSS::remove(GSSnode* node) |
void GSS::remove(GSSnode* node) |
||
{ |
{ |
||
Line 47: | Line 47: | ||
delete node; |
delete node; |
||
} |
} |
||
</syntaxhighlight> |
|||
</source> |
|||
== References == |
== References == |
Revision as of 10:28, 25 July 2020
In computer science, a graph-structured stack (GSS) is a directed acyclic graph where each directed path represents a stack. The graph-structured stack is an essential part of Tomita's algorithm, where it replaces the usual stack of a pushdown automaton. This allows the algorithm to encode the nondeterministic choices in parsing an ambiguous grammar, sometimes with greater efficiency.
In the following diagram, there are four stacks: {7,3,1,0}, {7,4,1,0}, {7,5,2,0}, and {8,6,2,0}.
Another way to simulate nondeterminism would be to duplicate the stack as needed. The duplication would be less efficient since vertices would not be shared. For this example, 16 vertices would be needed instead of 9.
Operations
GSSnode* GSS::add(GSSnode* prev, int elem)
{
int prevlevel = prev->level;
assert(levels.size() >= prevlevel + 1);
int level = prevlevel + 1;
if (levels.size() == level)
{
levels.resize(level + 1);
}
GSSnode* node = findElemAtLevel(level, elem);
if (node == nullptr)
{
node = new GSSnode();
node->elem = elem;
node->level = level;
levels[level].push_back(node);
}
node->add(prev);
return node;
}
void GSS::remove(GSSnode* node)
{
if (levels.size() > node->level + 1)
if (findPrevAtLevel(node->level + 1, node)) throw Exception("Can remove only from top.");
for (int i = 0; i < levels[node->level].size(); i++)
if (levels[node->level][i] == node)
{
levels[node->level].erase(levels[node->level].begin() + i);
break;
}
delete node;
}