1860 United States presidential election in Wisconsin

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1860 United States presidential election in Wisconsin

← 1856 November 6, 1860 1864 →
 
Nominee Abraham Lincoln Stephen A. Douglas
Party Republican Democratic
Home state Illinois Illinois
Running mate Hannibal Hamlin Herschel V. Johnson
Electoral vote 5 0
Popular vote 86,113 65,021
Percentage 56.59% 42.73%

County Results

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

The 1860 United States presidential election in Wisconsin was held on November 6, 1860, as part of the 1860 United States presidential election. State voters chose five electors to the Electoral College, who voted for president and vice president.

Wisconsin was won by the Republican Party candidate Abraham Lincoln and his running mate Hannibal Hamlin. They defeated the Democratic Party candidate Stephen A. Douglas and his running mate Herschel V. Johnson. Lincoln won the state by a margin of 13.86%.

Results[edit]

1860 United States presidential election in Wisconsin[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Abraham Lincoln of Illinois Hannibal Hamlin of Maine 86,113 56.59% 5 100.00%
Democratic Stephen Arnold Douglas of Illinois Herschel Vespasian Johnson of Georgia 65,021 42.73% 0 0.00%
Southern Democratic John Cabell Brekinridge of Kentucky Joseph Lane of Oregon 888 0.58% 0 0.00%
Constitutional Union John Bell of Tennessee Edward Everett of Massachusetts 161 0.11% 0 0.00%
Total 152,183 100.00% 5 100.00%

See also[edit]

References[edit]

  1. ^ "1860 Presidential General Election Results - Wisconsin".